I was thinking of posting this in the Rules Forum but in Reality it is not a Rules Question.
In 2 Ball Ambrose The accepted method of calculating handicaps has been to add the 2 Caps together & divide by 4.
Was wondering what I seekers would suggest for the following example. If I play with my regular partner we would have 38 shots combined which totals to 9.2 shots for the event.
Another pair in the event play off +3 & +2. Combined handicap of +5. Divide by 4 & their Comp handicap of +1.25 is actually more than either players individual handicap.
Any suggestions?

Shoot 5 under off the stick.

14.2 under (nett) ought to see them off.

Multiply each handicap by the number of members on the team:
3×2 = 6
2×2 =4
Handicap 10
then divide by 2 x the number of members in the team (4)
10/4 = 2.5

I was never the best student at Algebra, Trigonometry or Calculus,
BUT,,,,, and you will have to forgive the way this comes out because a keyboard doesn’t give the ability for mathematical equations. then again it probably does, just that I don’t know how to do it :) When I say over it is like working out percentages, if that helps. The thing is they are already below handicap, so the combination of handicaps cannot be less than the individual handicaps used to calculate the outcome.

plus 3 plus plus 2 divided by 4 equates to 3 plus 2 over 4 which equates to 7 over 2. Their handicap for a 2man ambrose is 3.5. Hope this helps.

I don’t know why, but the + seems to cause an underline so I have revised the way the above has been written to hopefully give a clearere understanding.

9.2 shots for the event.
Another pair in the event play off +3 & +2. Combined handicap of +5. Divide by 4 & their Comp handicap of +1.25 is actually more than either players individual handicap.
Any suggestions?

http://www.golflink.com.au/...

38 divided by 4 = 9.5 ….

.....so 14.5 under (nett) should kick their butt.

Big ask in a 2 man Putts….

I was thinking of posting this in the Rules Forum but in Reality it is not a Rules Question.
In 2 Ball Ambrose The accepted method of calculating handicaps has been to add the 2 Caps together & divide by 4.
Was wondering what I seekers would suggest for the following example. If I play with my regular partner we would have 38 shots combined which totals to 9.2 shots for the event.
Another pair in the event play off +3 & +2. Combined handicap of +5. Divide by 4 & their Comp handicap of +1.25 is actually more than either players individual handicap.
Any suggestions?

http://www.golflink.com.au/...

Multiply the +5 by 1.25, rather than 0.25?

I would think the fairest result for a plus handicap team would be a team handicap that penalises them 3/4 of their combined handicap, as it does those that are not on a plus handicap.

So in the example provided, 3+2=5, so handicap them as plus 5, and an additional plus 5×3/4 = 3.75….so they should be off plus 8.75.

As Goldy suggests the formula for calculating plus h/caps in Ambrose events are as follows

1/4 of h/cap = multiply by 1.75 (2 person)

1/8 of h/cap = multiply by 1.875 (4 person)

1/6 of h/cap = mu;tiply by 1.75 (3 person)

Not a common occurrence but confusing when it occurs

As Goldy suggests the formula for calculating plus h/caps in Ambrose events are as follows

1/4 of h/cap = multiply by 1.75 (2 person)

1/8 of h/cap = multiply by 1.875 (4 person)

1/6 of h/cap = mu;tiply by 1.75 (3 person)

Not a common occurrence but confusing when it occurs

Where would I find this written ? They are sure to ask.

As vice captain of our senior group I was given several laminated sheets that date back some years as an aid to handicapping. Unfortunately I cannot produce evidence as to their accuracy but we have used this system for many years and yes we do have some in our group with plus h/caps.

Big ask in a 2 man Putts….

The key to success is to learn to do something right, then do it right every time. Oh I wish…..

Now a two time winner of the treasured WBT.

Nett 57 or 58 usually wins at our course in a 2 man. That is usually 4/5 under off the stick and 8/9 handicap.

I’m not sure what the problem is with these two players having plus 1.25. Yes it is effectively more than either of their handicaps but they would probably have to shoot 14/16 under to have any chance of winning the nett.

OK Lanesend. Thank you for that Information. Might have a google around & see If I can find anything in writing. Otherwise will have to pursued the Powers that be that this is the way to go.

You mean I jagged it?

Amazing.

Big ask in a 2 man Putts….

The key to success is to learn to do something right, then do it right every time. Oh I wish…..

Now a two time winner of the treasured WBT.

Nett 57 or 58 usually wins at our course in a 2 man. That is usually 4/5 under off the stick and 8/9 handicap.

I’m not sure what the problem is with these two players having plus 1.25. Yes it is effectively more than either of their handicaps but they would probably have to shoot 14/16 under to have any chance of winning the nett.

Nine out of ten people believe that out of ten people, one person will always disagree with the other nine!

Let me see If i can explain this better. Next weekend we are having a 2 ball Ambrose, open comp, over 36 holes.
The fact that it is 2 rounds will work in favour of the lower markers( more consistant )
Guys at the club yesterday asked me what the rules were re the situation of the + markers. I posted here & asked the Question. Weather anyone uses this information is not my call.

Ring the Maths Dept at Qld Uni Pom, I’m sure one of the mathematicians there will help you out and provide the written calculus for proof.

Might just do that.:-)

I was thinking of posting this in the Rules Forum but in Reality it is not a Rules Question.
In 2 Ball Ambrose The accepted method of calculating handicaps has been to add the 2 Caps together & divide by 4.
Was wondering what I seekers would suggest for the following example. If I play with my regular partner we would have 38 shots combined which totals to 9.2 shots for the event.
Another pair in the event play off +3 & +2. Combined handicap of +5. Divide by 4 & their Comp handicap of +1.25 is actually more than either players individual handicap.
Any suggestions?

http://www.golflink.com.au/...

you lost me after this bit, ...I was thinking of posting this in the Rules Forum

Big ask in a 2 man Putts….

The key to success is to learn to do something right, then do it right every time. Oh I wish…..

Now a two time winner of the treasured WBT.

Nett 57 or 58 usually wins at our course in a 2 man. That is usually 4/5 under off the stick and 8/9 handicap.

I’m not sure what the problem is with these two players having plus 1.25. Yes it is effectively more than either of their handicaps but they would probably have to shoot 14/16 under to have any chance of winning the nett.

Nine out of ten people believe that out of ten people, one person will always disagree with the other nine!

Let me see If i can explain this better. Next weekend we are having a 2 ball Ambrose, open comp, over 36 holes.
The fact that it is 2 rounds will work in favour of the lower markers( more consistant )
Guys at the club yesterday asked me what the rules were re the situation of the + markers. I posted here & asked the Question. Weather anyone uses this information is not my call.

http://www.golflink.com.au/...

All good Pom, no further explanation needed. I think +1.25 would be adequate because their chances of winning the nett over 2 rounds are very slim; impossibe if they get taken any lower?

Gross they should be a shoe in : )

Actually I’ve changed my mind. If you had two scratch golfers you could divide or multiply it by whatever you want and they are still going to be off scratch ie the average of their handicaps. I think it would be easier to say that this applies to plus handicaps too.

I always thought + handicappers were calculated multiplied by 2

In this instance it would be as below

3 +2 = +5

+5×2 = +10

We have alwayse broken this down if there are mixed handicaps
Eg
+2 and 6 handicapper would calculate as below

2×2 = +4
6 \divided 4 = 1.5
+4 1.5 = +2.5

The problem I see with that Strugglin (and the reason that I changed my mind) is that it goes against the trend that occurs as a group’s handicap gets lower. If we continue with two person ambrose as an example…
Average of players’ handicaps – 30, ambrose handicap – 15 (difference 15)
Average of players’ handicaps – 20, ambrose handicap – 10 (difference 10)
Average of players’ handicaps – 10, ambrose handicap – 5 (difference 5)
Average of players’ handicaps – scr, ambrose handicap – scr (difference 0)
In other words, as the average of the players’ handicaps decreases, so does the difference between the average of their handicaps and their ambrose handicap. An average handicap of +5 is lower than an average handicap of scr, yet the consnsus seems to be that the difference between their average handicap and ambrose handicap should start increasing again.

Unfortunately you will never get a concrete answer as Ambrose is not an official format and therefore is not covered by the Rules of Golf.

It’s really about making a decision that is fair and agreed apron before the beginning of play.

Unfortunately you will never get a concrete answer as ambrose is not an official format and therefore is not covered by the Rules of Golf.

It’s really about making a decision that is fair and agreed apron before the beginning of play.